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i safari File Edit View History Bookmarks Window Help 42%)D Mon 1:07 PM webassign.net Week 13 -Chapters 29 & 30 array ng Velocity selector Need Help? · Read It Watch It 3.+-11 points SerPSET9 29 P 029 My Notes A velocity selector consists of electric and magnetic fields described by the expressions E = E k and B = B j, with B = 14.0 mT. Find the value of E such that a 730-eV electron moving in the negative x direction is undeflected. Need Help? Read it I watch it Submit Answer Save Progress Practice Another Version 4. 11 points | Previous Answers SerPSET9 29.P.033. My Notes A conductor carrying a currentI negative y direction. 14.5 A is directed along the positive x axis and perpendicular to a uniform magnetic field. A magnetic force per unit length of 0.121 N/m acts on the conductor in the (a) Determine the magnitude of the magnetic field in the region through which the current passes. 0.00834 Ps

Explanation / Answer

Energy of electron = 0.5mv^2 = 730 eV
v^2 = 2*730*1.6*10^-19 (joule)/9.1*10^-31 = 256.70*10^12
v = 16.02*10^6 m/s
vector > v = 16.02*10^6 (-i)
for remaining undeflected ----> net force is zero
Fnet = 0 = qE + q[v x B] >> vector
E + [v x B] = 0
E (k) + [v (-i) x (+j)] = 0
E (k) + vB [-k] = 0
E (k) = vB [k] comparing magnitudes
E = vB = 16.02*10^6*14.0 *10^-3  
E = 2.243*10^5 volt/meter= 224.3 KV/m

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