i need to write a program which deals with functions in c language by prompting

Question

i need to write a program which deals with functions in c language by prompting the user for a mathematical expression. It will then print the result of that expression which will support the following operators–+, -, x, X, *, /, m, and M. m will stand for minimum. M will stand for maximum.


i need to declare, define and call the following functions:

// Returns the result of value_1 + value_2
double add(double value_1, double value_2);

// Returns the result of value_1 - value_2
double subtract(double value_1, double value_2);

// Returns the result of value_1 * value_2
double multiply(double value_1, double value_2);

// Returns the result of numerator / denominator
double divide(double numerator, double denominator);

// Returns the minimum number between value_1 and value_2
double minimum(double value_1, double value_2);

// Returns the maximum number between value_1 and value_2
double maximum(double value_1, double value_2);


i need to Use a switch statement when deciding which expression to evaluate
All output will be displayed with 3 digits of precision
3 different operators will be supported for multiplication
No output will occur in the function definitions

When reading the operator in C with scanf you will need to read in a single character. In order to allow for the leading white space, your scanf call should look like

scanf(" %c", &binary_operator);

examples for outputs:

Please enter an expression (ex: 3.23 + 12): 4.3 + 2.7
4.300 + 2.700 = 7.000

Please enter an expression (ex: 3.23 + 12): 2 - 5.8
2.000 - 5.800 = -3.800

Please enter an expression (ex: 3.23 + 12): 19.1 x 2
19.100 x 2.000 = 38.200

Please enter an expression (ex: 3.23 + 12): 20 / 6
20.000 / 6.000 = 3.333

Please enter an expression (ex: 3.23 + 12): 5 h 9
Illegal expression.

Please enter an expression (ex: 3.23 + 12): 4.3 m 1.01
4.300 m 1.010 = 1.010

Please enter an expression (ex: 3.23 + 12): 4.3 M 1.01
4.300 M 1.010 = 4.300

Explanation / Answer

#include<stdio.h>

// Returns the result of value_1 + value_2

double add(double value_1, double value_2)

{    return value_1+value_2;}
// Returns the result of value_1 - value_2

double subtract(double value_1, double value_2) 

{    return value_1-value_2;}
// Returns the result of value_1 * value_2

double multiply(double value_1, double value_2)

  {    return value_1*value_2;}
// Returns the result of numerator / denominator

double divide(double numerator, double denominator)

{    return numerator/denominator;}
// Returns the minimum number between value_1 and value_2

double minimum(double value_1, double value_2)

{    if(value_1<value_2) return value_1;    else return value_2;}
// Returns the maximum number between value_1 and value_2

double maximum(double value_1, double value_2) 

 {    if(value_1>value_2) return value_1;   

else return value_2;}

int main(){   

double value1,value2;   

char operater;   

printf("Please enter an expression (ex: 3.23 + 12)");   

scanf("%f",&value1);   

scanf("%c",&operater);   

scanf("%f",&value2); 

 printf("%c",operater);   

switch(operater)   

{       

case '+': printf("%4f+%f= %f",value1,value2,add(value1,value2)); break;       

case '-':  printf("%f %c %f= %f",value1,operater,value2,subtract(value1,value2)); break;       

 case '*':  printf("%f %c %f= %f",value1,operater,value2,multiply(value1,value2)); break;         

case '/':  printf("%f / %f= %f",value1,value2,divide(value1,value2)); break;           

case 'm':  printf("%f m %f= %f",value1,value2,minimum(value1,value2)); break;           

case 'M':  printf("%f M %f= %f",value1,value2,maximum(value1,value2)); break;           

default: printf("wrong input"); break;

}                                                                   }

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