A 1.00 kg mass oscillates according to the equation x =0.600cos8.20 t , where x

Question

A 1.00 kg mass oscillates according to the equation x=0.600cos8.20t, where x is in meters and t is in seconds.

Part A

Determine the amplitude.

Part B

Determine the frequency.

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Part C

Determine the total energy.

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Part D

Determine the kinetic energy when x = 0.340 m .

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Part E

Determine the potential energy when x= 0.340 m .

A 1.00 kg mass oscillates according to the equation x=0.600cos8.20t, where x is in meters and t is in seconds.

Part A

Determine the amplitude.

Part B

Determine the frequency.

f=

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Part C

Determine the total energy.

Etotal=

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Part D

Determine the kinetic energy when x = 0.340 m .

Ekinetic=

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Part E

Determine the potential energy when x= 0.340 m .

Epotential=

Explanation / Answer

amplitude = 0.600m

frequency = 8.20/2pi

frequency = 1.304 Hz

TE = [1/2][1.00 * 8.20^2 * (0.600)^2]

TE = 12.1032 J

PE = 1/2 * 1.00 * 8.2^2 * 0.34^2

PE = 3.8864 J

KE = TE - PE = 8.2171 J

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