A barbell is mounted on a nearly frictionless axle through its center. The low-m

Question

A barbell is mounted on a nearly frictionless axle through its center. The low-mass rod has a length d 0.22 m, and each ball has a mass m = 0.4 kg. At this instant, there are two forces of equal magnitude F applied to the system as shown, with the directions indicated, and at this instant the angular velocity is 90 radians/s, counterclockwise, and the angle = 35 degrees. In the next 0.004 s, the angular momentum relative to the center increases by an amount 5.5 x 10 kg.m2/s. What is the magnitude of each force? Additional Materials | section 11.8

Explanation / Answer

the change in angular momentum per unit of time is equal to the torque applied to an object

dLa/dt=Tnet

torque= r(F)sin(theta)

dLa/dt= r(F)sin(theta)

so 5.5e-4/.004 = 0.11(F)sin35°

F= 2.18 N

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