details please FULL SCREEN PRINTER VERSION BACK NEXT Chapter 09, Problem 042 1 Y

Question

details please

FULL SCREEN PRINTER VERSION BACK NEXT Chapter 09, Problem 042 1 Your answer is partially correct. Try again. An object, with mass 28 kg and speed 23 m/s relative to an observer, explodes into two pieces, one 3 times as massive as the other; the explosion takes place in deep space. The less massive piece stops relative to the observer. How much kinetic energy is added to the system during the explosion, as measured in the observer's reference frame? Number 78997.3 Units the tolerance is +/-290 Click if you would like to Show Work for this question: Open Show Work SHOW HINT INK 1O TEXI LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE Question Attempts: 7 of 10 used SAVE FOR LTERSUBRIT ANSWER Version All Rights Reserved. A Division of Johnylerasnsinc.

Explanation / Answer

Conserving momentum

Initial momentum=final momentum

4m*23=3m*v

We got v=30.67 m/s

Initial KE=0.5*28*23*23=7406

Final KE=0.5*21*30.67*30.67=9874.67

Energy added=2468.67 J

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.