#8 (a-c) (109%) Problem 8: A coal car m-3525 kg is rolling down the tracks at a

Question

#8 (a-c)

(109%) Problem 8: A coal car m-3525 kg is rolling down the tracks at a velocity of v, 4.9 m/s when a loader drops a load of coal m2 5255 kg into the car. Randomized Variables m 3525 kg m2-525sk = 4.9m/s 3396 Part (a) what is the momentum of the system in (kg·m) s before the coal is added? 3396 Part (b) What is the velocity after the coal is added in meters per second? à 33% Part (c) If you measured the final velocity of the car to be 1 m/'s and the initial mass of the car remains the same, how much coal was added to the car in kg? Grade Summary potential 100% Submissions cotan asin atan acotansinh cosh tanhcotanh0 Attempts remaning (1% per attempt) detailed view acos( 4 5 6 1 23 . Degrees Radians vo

Explanation / Answer

here,

m1 = 3525 kg

m2 = 5255 kg

initial velocity , vi = 4.9 m/s

a)

the momentum of system before the coal is added , Pi = m1 * v1 = 3525 * 4.9 kg.m/s

Pi = 1.73 * 10^4 kg.m/s

b)

let the final velocity of car be vf

using conservation of momentum

Pi = (m1 + m2) * vf

17300 = ( 3525 + 5255) * vf

solving for vf

vf = 1.97 m/s

the final velocity of car is 1.97 m/s

c)

final velocity , vf = 1 m/s

let the mass of coal added be m2'

using conservation of momentum

Pi = (m1 + m2') * vf

17300 = ( 3525 + m2') * 1

m2' = 1.4 * 10^4 kg

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