My Notes O Ask SerCP9 4 P044 WI A crate of mass 45.0 kg is being transported on

Question

My Notes O Ask SerCP9 4 P044 WI A crate of mass 45.0 kg is being transported on the flatbed of a pickup truck. The coefficient of static friction between the crate and the truck's flatbed is o.270, and the coefficient of kinetic friction is 0.160. (a) The truck accelerates forward on level ground. What is the maximum acceleration the truck can have so that the crate does not slide relative to the truck's flatbed? m/s2 (b) The truck barely exceeds this acceleration and then moves with constant acceleration, with the crate sliding along its bed. What is the acceleration of the crate relative to the ground? m/s2 Need Help? LWatch Talk to Tuter Talk to a Tutor

Explanation / Answer

here,

mass of carte , m = 45 kg

coefficient of static friction , us= 0.27

a)

the maximum accelration of the truck be a

frictional force = m * a

us * m * g = m * a

a = 0.27 * 9.81 =2.64 m/s^2

the maximum accelration is 2.64 m/s^2

b)

as the crate is sliding across the bed,the accelration is 2.64 m/s^2

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