A beaker is filled to the brim with water, A solid object of mass 3.00 ko is low

Question

A beaker is filled to the brim with water, A solid object of mass 3.00 ko is lowered into the beaker so the object is fully submerged in the water (see the drawing). During this process, 2.00 kg of water flows over the rim and out of the beaker. What is the buoyant force that acts on the submerged object, and, when released, does the object rise, sink, or remain in place? 19.6 N. The object sinks 19.6 N. The object rises 19.6 N. The object remains in place 294N. The object sinks 29.4 N. The object rises

Explanation / Answer

Here,

as 2 Kg of water flow when the object is placed

2 Kg water is displaced when the object

Using Archimedes principle

Buoyant force = weight of displaced water

Buoyant force = 2 * 9.8

Buoyant force = 19.6 N

as the mass of object is more than mass of water displaced

the object will sink

the correct option is 19.6 N , the object sinks

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.