4) Barky the Physics Dog jumps in the air with a speed of 100 m/s at an angle of

ID: 1791913 • Letter: 4

Question

4) Barky the Physics Dog jumps in the air with a speed of 100 m/s at an angle of 36.9° from level ground to level ground.

What is Barky’s initial velocity in the vertical direction? (HINT: sin36.9 = vi /100)

What is Barky’s horizontal constant velocity? (HINT: cos36.9 = vc /100)

What is Barky’s final vertical velocity at maximum height?

How long does it take Barky to reach his maximum height?

What is Barky’s total time in the air? (HINT: Up and back down again)

What is Barky’s horizontal displacement?

1. initial vertical velocity = Answer m/s

2. hoirizontal velocity = Answer m/s

3. final velocity at maximum height = Answer m/s

4. time to maximum height = Answer s

5. total air time = Answer s

6. horizontal displacement = Answer m

1) Initial vertical velocity = v sin a =100 sin 36.9 = 60.04 m/s

2) Horizontal velocity = v cos a = 100 cos 36.9 = 79.96 m/s

3) Velocity at maximum height will be only horizontal velocity = 79.96 m/s

4) Time to maxium height = u sin a /g = 60.04 / 9.8 = 6.13 s

5) total air time = 2*time to reach maximum height = 2*6.13 = 12.25 s

6) X = Ux*t

= 79.96*12.25 = 979.75 m

horizontal displacement = 979.75 m

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