The bar is moving to the left Bexternal bar S-31) Consider the situation depicte

Question

The bar is moving to the left Bexternal bar S-31) Consider the situation depicted in the figure above: The conducting bar is moving at a speed (v) of 4 m/s to the left across conducting rails that are 10 cm apart (w). The present length of the bar from the connected end of the rails is 20 cm (L). The strength of the external magnetic field is a constant and uniform .034 T (B external). a) What is the voltage induced in the circuit formed by the bar and the rails? b) What direction is the induced current in the circuit (clockwise or counter)? c) If the circuit has a resistance of 5 , what will the induced current be in the circuit due to this induced voltage?

Explanation / Answer

Here ,

a)

voltage induced in the circuit = B*v*L

voltage induced in the circuit = 0.034 * 4 * 0.10

voltage induced in the circuit = 0.0136 V

b)

AS the flux in the loop is decreasing

the direction of current induced in the loop is clockwise.

c)

induced current = voltage induced in the circuit/R

induced current = 0.0136/5

induced current = 2.72 *10^-3 A

induced current = 2.72 mA

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