A 200 kg roller coaster starts from rest. The ride reaches a maximum height of 3
ID: 1792787 • Letter: A
Question
A 200 kg roller coaster starts from rest. The ride reaches a maximum height of 30 m and a top speed of 30
m/s. 40 seconds after starting, the roller coaster moves at 5.0 m/s on a horizontal section of track that is 5.0 m
below the starting height. There are no elastic (spring) forces involved. For the whole ride (40 seconds), the
total work done on the roller coaster is _____ and the work done by gravity is _____.
THIS was all the info given. No Graphich or further instructions were given. I believe it was to be a more trickier question by given more information than needs to be used.
a) 0 J, 0 J
b) 0 J, -10,000 J
c) 2500 J, -10,000 J
d) 2500 J, 10,000 J ***
e) -10,000 J, 10,000 J
If hand written please be neat and show work. Thank you for your help.
Types of notation that is used in the class: mph or 1/2mv^2
Explanation / Answer
from work- energy theorem,
total work done = change in KE
W = 200 ( 5^2 - 0^2) /2
W = 2500 J
Work done by gravity = - m g delta(h)
= - 200 x 10 x (-5)
= 10000 J
Ans(d)
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