ics: 4378 9.16 s previous 2 of 5 Exercise 9.16 0-581 rad lus At t 0 a grinding w
ID: 1793273 • Letter: I
Question
ics: 4378 9.16 s previous 2 of 5 Exercise 9.16 0-581 rad lus At t 0 a grinding wheel has an angular velocity of 30.0 rad/s. It has a constant angular acceleration of 30.0 rad/s2 until a circuit breaker trips at time t 2.30s. From then on, it turns through an angle 433 rad as it coasts to a stop at constant angular acceleration Correct lome Part B nts At what time did it stop? ols t 8.050 Submit Incorrect; Try Again; 2 attempts remaining; no points deducted Part C What was its acceleration as it slowed down? rad/sExplanation / Answer
(A)
= + t
= + t + ½t²
² = ² + 2
= 0 + 30(2.30) + ½(30.0)2.30²
= 148.35 rad
Through what total angle did the wheel turn between t=0 and the time it stopped?
= 148.35 + 433
= 581.35 radians <<<ANSWER
(C) What was the wheel's angular acceleration as it slowed down?
When the circuit breaker trips :
= 30.0 + 30.0(2.30)
= 99 rad/s
0² = 99² + 2433
= -11.32 rad/s² <<<ANSWER
(B)
= ½t²
433 = ½(11.32)t²
t = 8.75 s
At what time does the wheel stop?
t = 2.30 + 8.75
t = 11.05 s <<<ANSWER
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