Two joggers run at the same average speed. Jogger A cuts directly north across t

Question

Two joggers run at the same average speed. Jogger A cuts directly north across the diameter of the circular track, while jogger B takes the full semicircle to meet his partner on the opposite side of the track. Assume their common average speed is 2.80 m/s and the track has a diameter of 160 m.

Part A

How many seconds ahead of jogger B does jogger A arrive?

SubmitMy AnswersGive Up

Incorrect; Try Again; 7 attempts remaining

Part B

How do their travel distances compare?

SubmitMy AnswersGive Up

Part C

How do their displacements compare?

SubmitMy AnswersGive Up

Part D

How do their average velocities compare?

Two joggers run at the same average speed. Jogger A cuts directly north across the diameter of the circular track, while jogger B takes the full semicircle to meet his partner on the opposite side of the track. Assume their common average speed is 2.80 m/s and the track has a diameter of 160 m.

Part A

How many seconds ahead of jogger B does jogger A arrive?

t =   s  

SubmitMy AnswersGive Up

Incorrect; Try Again; 7 attempts remaining

Part B

How do their travel distances compare?

dA, dB =   m  

SubmitMy AnswersGive Up

Part C

How do their displacements compare?

xA, xB =   m north

SubmitMy AnswersGive Up

Part D

How do their average velocities compare?

vA, vB =   m/s north

Explanation / Answer

Using circle geometry, the semicircle is times as long as the diameter, so

a)

A takes

t = d / v = 160m / 2.8m/s = 57.14 s

and B takes 57.14s * = 179.59 s, so A arrives 122.45 seconds ahead of B.

b)

1:, or 160m : 502.85 m

c)

displacements are equal at 160 m

d)

A: Vavg = 2.8 m/s north

B: Vavg = 2.8m/s / north = 0.8909 m/s north (It took him times as long)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.