Table 1 Block Mass (kg) Volume (L*W*H) (m^3) Density (kg/m^3) Aluminum 0.087 kg
ID: 1793416 • Letter: T
Question
Table 1
Block
Mass (kg)
Volume (L*W*H) (m^3)
Density (kg/m^3)
Aluminum
0.087 kg
0.03177*0.03214*0.03103
2745.86
Iron
.253 kg
0.03285*0.03203*0.03173
7578.02
Table 2
Block
Weight in Air (N)
Weight in Water (N)
Weight in Alcohol (N)
Weight in Oil (N)
Buoyant Force of Water (N)
Buoyant Force of Alcohol (N)
Buoyant force of Oil (N)
Aluminum
.8515
.5470
.5783
.5234
Iron
2.428
2.092
2.124
2.060
Find the Buoyant Force of water, Alcohol and Oil
Using the volume calculation in table 1 and the fact that water has a density of 1g/cm^3, calculate the mass of the displaced water, the multiply that by gravity to get the weight of the displaced water. Compare the number to your buoyant force in water. Do your results obey Archimedes’ principle?
Take the buoyant force of alcohol and divide it by the volume of the block to get the weight density of alcohol. Divide by gravity to get the density of the alcohol. Do the same for the oil. Rank the densities of water, alcohol and oil from the largest to smallest. Rank the buoyant forces of water, alcohol and oil from largest to smallest. How do you your rankings compare? Calculate the specific gravity of the 3 fluids. Rank from smallest to largest.
Block
Mass (kg)
Volume (L*W*H) (m^3)
Density (kg/m^3)
Aluminum
0.087 kg
0.03177*0.03214*0.03103
2745.86
Iron
.253 kg
0.03285*0.03203*0.03173
7578.02
Explanation / Answer
Volume of aluminium, Val = Mass/density = 3.1684*10^-5 m^3
Volume of iron Vfe = Mass/density = 3.3386*10^-5 m^3
for water
aluminium
buoyant force = 1000*Val*g = 0.31082004 N
weight in water = weight - buoyant force = 0.54264996 N
from the table, weight in water = 0.5470 N
iron
buoyant force = 1000*Vfe*g = 0.32751666 N
weight in water = 2.10048334 N
from table, weight in water = 2.092 N
for alcohol
aluminium, buoyant force = 789*Val*g = 0.24523701156 N
weight in alcohol = 0.60626298844 N
from table, weight = 0.5783 N
iron
buoyant force = 0.25841064474 N
weight in alcohol = 2.16958935526 N
weight from table = 2.124 N
for oil
aluminium, buoyant force = 0.287508537 N
weight in oil = 0.563991463 N
weight from table = 0.5234 N
for iron
buoyant force = 0.3029529105 N
weight in oil = 2.1250470895 N
from table, W =2.060 N
hence the results are close to the results calculated theoretically
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