Table 1 Average Value Voltage across R, Vr (V) = .5958 Current Ir, (A) = .058 Ta
ID: 2265156 • Letter: T
Question
Table 1
Average Value
Voltage across R, Vr (V) = .5958
Current Ir, (A) = .058
Table 2
Average Value
Voltage across R, Vrc (V) = .4918
Voltage across C, Vc (V) = 1.58
Table 3
Average Value
Voltage across R, Vrl (V) = .533
Voltage across L, Vl (V) = .3194
Using the average values (VRand IR) from Table 1, calculate Vrms = (0.707VR) and the value of the resistor R (in ohms).
Vrms = _______________ V
R = __________________ Ohms
Calculate the current amplitude (IC = VRC/R) using the average value of VRCfrom Table 2.
Ic = ______________________ A
Calculate the reactance of the capacitor (XC = VC/IC) using the average value of VC from Table 2.
Xc = _____________________ Ohms
Calculate the theoretical reactance of the capacitor using XC = 1/?C.
Xc, theoretical = ______________________ Ohms
Calculate the current amplitude (IL = (VRL
Explanation / Answer
Vrms = 0.707*0.5958=0.421
R = 0.5958/0.058=10.27 ohms
Ic = 0.4918/10.27=0.0479 A
Xc = 1.58/0.0479=32.99
you didnt w or C so we cant calculate Xc theoretical
Il = .533*2/10.27=0.104
XL = 0.3194/0.104=3.07
you didnt give w or L so we can't calculate Xl theoretical
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