Home-LookingGlass WileyPLUS tps//edugen.wileyplus.com/edugen/ti/main.uni your bo

Question

Home-LookingGlass WileyPLUS tps//edugen.wileyplus.com/edugen/ti/main.uni your bookmarks here on the bookmarks bar. Import bookmarks now ... Return to Blackboard ell, Physics, 10e I System Announcements (1 Unread) PRINTER VERSION BACK NEX Chapter 06, Problem 11 Your answer is partially correct. Try again. A 167-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 26.8 ° below the horizontal. The coefficlent of kinetic friction is 0.261. What should be the magnitude of P, so that the net work done by it and the kinetic frictional force is zero?

Explanation / Answer

Given

mass of the crate m = 167 kg

the force applied is P making an angle theta = 26.8 degrees below the horizontal

the coefficient of kinetic friction is mue_k = 0.261

work done W = F*s cos theta

here work will be done by both the applied force (push) and the frictional force

to make the net work done = 0 , the forces should act on the opposite directions

that is P*s cos theta = mue_k(mg + P sin theta)

P cos 26.8 = 0.261(167*9.8 + P sin 26.8)

P = 551.23 N

the push required for the net work done on the crate become zero with mue_k =0.261 is 551.23 N

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.