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Need Help? 10. -/3 points SerCP9 7 P041 MI.FB A satellite is in a circular orbit

ID: 1793974 • Letter: N

Question

Need Help? 10. -/3 points SerCP9 7 P041 MI.FB A satellite is in a circular orbit around the Earth at an altitude of 2.92 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law: GMs so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98% 1024 kg.) (b) Find the speed of the satellite. 0 km/s (c) Find the acceleration of the satellite. m/s2 toward the center of the earth Need Help?Read ress 11. 0/2 points | Previous s SerCP9 7 P042 An artificial satellite circling the Earth completes each orbit in 101 minutes. (The radius of the Earth is 6.38 x 106 m. The mass of the Earth is 5.98 x 1024 kg.) (e) Find the alttude of the satelite

Explanation / Answer

given h = 2.92*10^6 m

Re = 6.38*10^6 m

Me = 5.98*10^24 kg

a. T^2 = (4pi^2/(GMs))(Re + h)^3

T = 8992.5868 s = 2.478 hours

b. speed = 2*pi*(Re + h)/T = 6.548 km/s

c. acceleration = (spped)^2/(Re + h) = 4.6117 m/s/s

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