How many butter, which has a usable energy content of 6.0 Cal/g (= 6000 cal/g),

Question

How many butter, which has a usable energy content of 6.0 Cal/g (= 6000 cal/g), would be equivalent to the change in gravitational potential energy of a 59 kg man who climbs 4.30 km? Assume that the average g for the climb is 9.80 m/s2.
the tolerance is +/-2%
How many butter, which has a usable energy content of 6.0 Cal/g (= 6000 cal/g), would be equivalent to the change in gravitational potential energy of a 59 kg man who climbs 4.30 km? Assume that the average g for the climb is 9.80 m/s2.
the tolerance is +/-2%
How many butter, which has a usable energy content of 6.0 Cal/g (= 6000 cal/g), would be equivalent to the change in gravitational potential energy of a 59 kg man who climbs 4.30 km? Assume that the average g for the climb is 9.80 m/s2.
the tolerance is +/-2%
the tolerance is +/-2%

Explanation / Answer

the change in potential energy is PE = m*g*h=59*9.8*4.30=2486.26 KJ

1KJ= 0.239 Cal

thus 6055.4KJ= 594.21Cal

mass required = energy / 6 Cal/g

m= 594.21/6 = 99.03 g

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