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Chrome File Edit View History Bookmarks People Window Help 4 80% , U.S. Mon 8:49

ID: 1794197 • Letter: C

Question

Chrome File Edit View History Bookmarks People Window Help 4 80% , U.S. Mon 8:49 PM University of South Alabama: xvi WileyPLUS Secure l https://edugenwileyplus.com/edugen/student/mainfr.uni WileyPLUSDifferential calculus. xC Chegg Study | Guided Solutior x Ahmad University of South D Apple iCloud Yahoo Bing W wikipedia R Facebook y Twitter The Weather Channel Yelp > Other Bookmarks WlleyPLUS: MyWlleyPLUS | Help | Contact Us I Log Out Calculus-based Physics I & II (PH 201-202) Apps LinkedIn WileyPLUS Halliday, Fundamentals of Physics, 10,e Home Read, Study&Practice; Gradebook ORION Downloadable eTextbook Assignment > open Assignment FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 19, Problem 024 At 259 K and 1.42 x 102 atm, the density of a gas is 1.26 x 10-5 g/cm3. (a) Find vrms for the gas molecules. (b) Find the molar mass of the gas. (a) Number (b) Number 201-25 044 050 Units 014 Units 026 LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM Review Question Attempts: 0 of 6 used SAVE FOR LATER SUBMIT ANSWER america.pd

Explanation / Answer

P V = n R T

P V = (m / M ) R T

P M = (m / V) R T

P M = rho R T

(1.42 x 10^-2 x 101325 Pa) (M ) = (1.26x 10^-5 x 10^3 kg / m^3) (8.314) (259)

M = 0.019 kg Or 19 grams

(A) V_rms = sqrt[ 3 R T / M ]

= 585 m/s


(B) molar mass = M = 19 grams

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