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Chrome File Edit View History Bookmarks People Window Help 4 80% , U.S. Mon 8:49 PM University of South Alabama: xvi WileyPLUS Secure l https://edugenwileyplus.com/edugen/student/mainfr.uni WileyPLUSDifferential calculus. xC Chegg Study | Guided Solutior x Ahmad University of South D Apple iCloud Yahoo Bing W wikipedia R Facebook y Twitter The Weather Channel Yelp > Other Bookmarks WlleyPLUS: MyWlleyPLUS | Help | Contact Us I Log Out Calculus-based Physics I & II (PH 201-202) Apps LinkedIn WileyPLUS Halliday, Fundamentals of Physics, 10,e Home Read, Study&Practice; Gradebook ORION Downloadable eTextbook Assignment > open Assignment FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 19, Problem 014 201-25 044 Pressure p, volume V, and temperature T for a certain material are related by hapter 19, Problem 014 where A and B are constants with values 348 J/K and 0.113 K2. Find the work done by the material if the temperature changes from 268 K to 295 K while the pressure remains constant. 026 Number Units the tolerance is +/-2% Review LINK TO TEXT LINK TO SAMPLE PROBLEM Question Attempts: 0 of 6 used SAVE FOR LATER SUBMIT ANSWER https://ed ugenwley plus.com/edugerishared/ass igrmennestraglisLuni?id=asnmt 2 1 1 6 1 america.pd

Explanation / Answer

given Ti = 268 K
Tf = 295 K

now, p = AT/V - BT^2/V
A = 348
B = 0.113

now work done = pdV
as pressure is constant
W = p(Vf - Vi)

348(268/Vi - 295/Vf) = 0.113(268^2/Vi - 295^2/Vf)
3079.646(268Vf - 295Vi) = 268^2Vf - 295^2Vi
753521.13274Vf = 821470.57 Vi
Vf = 1.09017588798 Vi
also
Vf - Vi = 0.0901758879 Vi
hence
W = 0.09017588 Vi*p

now,
pVi = ATi - BTi^2 = 85147.888
hence
W = 7678.285 J

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