(13%) Problem 3: A candle (ho-0.32 m) is placed to the left of a diverging lens(
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Question
(13%) Problem 3: A candle (ho-0.32 m) is placed to the left of a diverging lens(f=-0.051 m). The candle is do-0.38 m to the left of the lens Randomized Variables ho 032 m f=-0.051 m do0.38 m 25% Part (a) Write an expression for the image distance, di Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: 5 (4% per attempt) detailed view 123 0 Submit Hint Hints: 1 % deduction per hint. Hi ints remaining: Feedback: 0%-deduction per feedback. - 25% Part (b) Numerically, what is the image distance in meters? - 25% Part (c) Is this real or virtual? - 25% Part (d) Numerically, what is the image height, h?Explanation / Answer
given
ho = 0.32 m
u = do = -0.38 m
f = -0.051 m
from lens formula
1/v - 1/u = 1/f
1/v = -1/0.051 - 1/0.38
v = -0.044965 m
hence di = 0.044965 m to the left of the lens
a. di = u*f/(u + f) = -do*f/(f - do)
b. di = 0.044965 m
c. the image is virtual
d. hi = 0.32*0.044965/0.38 = 0.03786542
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