An inductor L-0.0345 H and a 35.0 resistor are connected in senes to a 3.50 volt

Question

An inductor L-0.0345 H and a 35.0 resistor are connected in senes to a 3.50 volt battery and a switch. Atte to complete the circuit. and a switch. At t-0 the switch is closed (a) What is the potential difference across the resistor immediately after the switch is closed? (b) What is the potential difference across the resistor a long time after the switch is dosed? (e) Which of the graphs below displays the general shape of the current versus time through the resistor in this circuit? I (A) (A) r (s) I (A) I (A) r (s) t (s) um value, d) From the time the switch is closed, how long does it take for the current to reach 63% of the m axi (e) All circuits have a self-inductance which is generally difficut to calculate precisely. For a single loop dircuit with a 2.35 a resistor, a single battery of 1.40 V, and a characteristic size (size of the loop) of 10.0 cm, the estimated inductance is 2 x 10 H. What is the time constant of this RL circuit?

Explanation / Answer

first four parts

a.) at t=0 inductor is like open circuit

so, no current hence potential difference across resistor =0

b.) after infinite time, I = Imax

so, V across resistor = 3.6 V

c.) (d) current should increase exponentially from zero to maximum value

d.) time taken for 63% is called time constant = L/R = 0.0345/35 = 0.985 ms

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