Problem 3 (7 points) A Poster of mass, m-230 kg is hanging at the end of a horiz

Question

Problem 3 (7 points) A Poster of mass, m-230 kg is hanging at the end of a horizontal uniform beam of length 4 .0 m as it is shown on the picture. The mass of the rod is 60 kg. A polyester rope, atached to the wall, is supporting the system. The angle, the rope makes with the beam, equals to 37-The system is in equilibrium. Find the tension force T in the rope. If you had to choose the rope, which one would you choose from the table below Find the horizontal and vertical components of the force exerted on the horizontal beam at the wall. F- Minimum breaking strength and safe load for polyester rope

Explanation / Answer

let

tension in the cable is T

mass of the poster,m=230 kg

mass of the beam, M=60 kg

length of the beam, L=4m

a)

at eqilibrium

net torque =0

L*T*sin(theta)-L*m*g -L/2*M*g =0

T*sin(theta)-m*g -1/2*M*g =0

T*sin(37)-230*9.8 -1/2*60*9.8=0

====> T=4233.86 N

b)

horizontal force component, FH=T*cos(theta)

FH=4233.86*COS(37)

FH=3381.31 N

and

along vertical line,

m*g+M*g=T*sin(theta)+FY

230*9.8+60*9.8=4233.86*sin(37)+FY

==> FY=294 N

vertical component, FY=294 N

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.