Tweedeldum and Tweedledee are carrying a uniform wooden board that is L = 3.00 m

Question

Tweedeldum and Tweedledee are carrying a uniform wooden board that is L = 3.00 m long and has a weight of w = 160 N . If Tweedledum applies an upward force of magnitude F1 = 60.0 N at the left end of the board, at what point and with what magnitude F2 of force does Tweedledee have to lift for the board to be carried?

Part C Complete the equation for the sum of the forces ?Fy in the y direction (the left side of the equation is given). Express your answer in terms of some or all of the variables w, F1, F2, L, and d.

Explanation / Answer

F1+F2 must equal the weight of the board, so we know that

F1+F2 = 160 N

we also know torques must balance; if we sum torques around the left end, the torque due to F1 is zero since it has no moment around the left end; the torque due to the weight of the board is

160 N*1.5m = 240 Nm

the torque due to F2 is F2*d where d is the distance from the left end where F2 is applied, so we have

F2 d = 240

since F1=60, we know that F2=160 N- 60N= 100 N, therefore,

d= 240 Nm/ 100 N = 2.4 m

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