In 2010, 433*10^6 tons of coal was produced from the stateof Wyoming. A. If the

Question

In 2010, 433*10^6 tons of coal was produced from the stateof Wyoming.

A. If the average heat content of the coal is 8,600 Btu/lb, and a typical coal-fired power plant operates at 40% efficiency, how many kW-hr of electricity was produced in 2010 using this coal?
1 ton=2000lb and 2.931*10^(-4)kW-hr=1Btu

B. In 2010, 4.128*10^12kW-hr of electricity was produced in the united states. What percentage of the nations electricity is fueled by the state of Wyoming?

I'm mostly confused about where efficiency comes into play but if you could explain this out that would be awesome.

Explanation / Answer

EFFICIENCY=(output electrical energy/input thermal energy)*100 1Btu=1055joules 1Kwh=3.6x10^6 joules input thermal energy in 1year,Ei=(433*10^6)(2000)(8600)(1055)=7.86x10^18 Joules output electrical energy,Eo=(40/100)*Ei=3.14x10^18joules=8.72x10^11kWh

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