Chapter review, Find the Following: Period, in seconds a. peak amplitude = 5 V,

Question

Chapter review, Find the Following:


Period, in seconds
a. peak amplitude = 5 V, frequency = 10 GHz, phase = 0 _________________
b. peak amplitude = 10 V, frequency = 5 THz, phase = (pi)/2 _________________
c. peak amplitude = 2 V, frequency = 1.5 MHz, phase = (pi) _________________

Frequencies in Hz:
a. 5 sec _________________
b. 12 pi sec _________________
c. 220 pi sec _________________

Bandwidth of the following analog signals, given the highest and lowest frequencies in each signal.
a. A signal whose highest frequency component is 6000 Hz and whose lowest frequency component is 2000 Hz, has a bandwidth of _________________
b. A signal whose highest frequency is 4000 Hz and whose lowest frequency component is 0 Hz, has a bandwidth of _________________
c. A signal whose highest frequency component is 800 MHz and whose lowest frequency component is 30 kHz, has a bandwidth of _________________

Digital Signals:
bit rate
a) A signal in which 1 bit lasts 0.001 s _________________
b) A signal in which 1 bit lasts 2 pi s _________________
c) A signal in which 10 bits last 20 pi s _________________


A device is sending out data at the rate of 1000 bps
a) How long does it take to send out 10 bits? _________________
b) How long does it take to send a character ( 1 character = 8 bits)? Give your answer in milliseconds (ms) _________________
c) How long does it take to send a file of 100,000 characters? _________________

If a layer 1 protocol defines 4 different levels for a digital signal, how many bits can be transmitted with each signal that is sent? _________________

A low pass or baseband channel has _________________ Hz as its lowest frequency component

A low pass or baseband channel is considered to have a wide bandwidth if the highest frequency component that it allows to pass is very _________________
a) large b) small

A low pass or baseband channel is considered to have a narrow bandwidth if the highest frequency component that it allows to pass is very _________________.
a) large b) small

The Shannon capacity formula provides a theoretical maximum data rate for a _________________ channel.
a) noisy b) noiseless

The Nyquist capacity formula provides a theoretical maximum data rate for a _________________ channel.
a) noisy b) noiseless

A signal travels from point A to point B. At point A, the power in the signal is 100 Watts. At point B, the power in the signal is 90 Watts. What is the attenuation of the signal in dB? _________________

The power in the signal in a particular channel is 12 mW. The power in the noise in that same channel is 12 piW.
a. What is the SNR of the system as a simple fraction? _________________
b. What is the SNRdB of the system? _________________

The distance between two ends of a transmission line is 12,000 km. If the propagation speed of electromagnetic energy on the line is known to be 2.4 x 108 meters/second, what is the propagation time?

_________________

The distance between two ends of a transmission line is 12,000 km. The digital bandwidth of the transmission line is 1 Gbps. If you send an email that is 2.5 kilobytes long, what is the transmission time?

___________________________________________________________________

This is a Bandwidth-Delay product question: How many bits can fit on a link with a 2 ms delay if the bandwidth of the link is
a) 1 MByte per second _________________
b) 10 MByte per second _________________
c) 100 Mbps _________________

Explanation / Answer

1.a 10^-10 b. 2*10^-13 c. 6.67*10^-7 2.a.0.2Hz b.0.0265 c. 0.0016 3.a 4000Hz b. 4000Hz c. 799970kHz

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