Six students (Dave, Michael, Ann, Joe, Jane, Bill) are attending a lecture in a

Question

Six students (Dave, Michael, Ann, Joe, Jane, Bill) are attending a lecture in a classroom
with 10 seats. The seats are in a single row as follows
A B C D E F G H I J
All valid seating arrangements are equally likely. By valid seating arrangement we mean that all
students have to sit down in a seat and students can not share seats. Here is an example of a valid
seating arrangement:
Dave - B, Michael - A, Ann - E, Joe - I, Jane - H, Bill - F
1. How many seating arrangements are there? Note that who sits where matters.
2. What is the probability of the seating arrangement: Dave - A, Michael - C, Ann - D, Joe - H,
Jane - I, Bill - J?
3. What is the probability that Dave sits in seat A?
4. What is the probability that seats A, C, D, H, I and J are occupied?
5. What is the probability that seat A is occupied?

Explanation / Answer

1.six will sit in 10 seats
so n=10P6=151200

2.p=1/151200

3.p=p(dave in seat A)*p(rest random)=(1/10)*(9P5)/10P6=.01

4.p=(10C6/10P6)=.0014

5.p=6*(9P5)/10C6=.6

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.