Suppose that an inductor is formed by N turns of a conductive wire wound around

Question

Suppose that an inductor is formed by N turns of a conductive wire wound around a magnetic material. The magnetic material forms a circular cylinder of radius r = 10 cm, and height h = 5 cm. The inductance of the inductor turns of N is defined as: L = ? / I (Henrys). Where L = inductance of the inductor, I = current flowing through the winding, ? ? = n = the total magnetic field which embraces all the winding turns (magnetic flux linkage), n = number of turns, ? = the net flux passing through the sectional area of a turn. Suppose the magnetic field around the winding can be approximated using the magnetic field at the center of a "loop" circular. Find the inductance of the inductor.

Explanation / Answer

we define R : reluctance L : inductance formula : L*R = N^2 (where N is the number of turns) ans Reluctance R = l/u0*A(u0 = 4pi*10^-7 is the permeabilityof vacuum,henry per metre) Area A: pi *r^2= .01pi m^2 length l = 0.05 meter so inductance of Inductor L= N^2*uo*A/l and flux per turn = Li/N (i is the current) ANSWERS L= N^2*uo*A/l flux per turn = Li/N please rate this.

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