answer= t (min)= 1mm treat cylindrical tanks used id vertical fluid - storage re

Question

answer= t (min)= 1mm treat cylindrical tanks used id vertical fluid - storage reservoirs, or standpipes. Problem 9.2 - 11 treats a water - filled vertical pipe. The hoop stress, sigma h, is given by Eq. 9.4, just as in the case of uniform internal pressure in a circular cylinder. According to Pascal's Law, the fluid develops hydrostatic pressure p = gamma h, where gamma is the specific weight of the fluid and h is the depth below the fluid surface of the point where the pressure h being calculated. For water, gamma = 62.4 lb/ft3 = 9.81 kN/m3 (See previous Note.) A vertical standpipe has an inside diameter of di = 3 m and is filled with water to a depth of h = 5 m. If the allowable hoop stress is 80 MPa, what is the minimum wall thickness of the tank to the nearest millimeter? (Neglect the restraint that the base exerts on the cylindrical tank.)

Explanation / Answer

Inside diameter di = 3m

Water depth h=5m

Weight density of water =9810 N/m^3

Hoops stress h = 80*10^6 N/m^2

Let "t" be the thickness of the cylinder

Inside pressure P=h=9810*5 = 49050N/m^2

But Hoops stress h =pd/2t

80*10^6 = 49050*3/2*t

t=9.196*10^-4 m

t= 1mm

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