Ammonia enters a condenser operating at steady state at225lbf/in^2 and 140degree
ID: 1815242 • Letter: A
Question
Ammonia enters a condenser operating at steady state at225lbf/in^2 and 140degree F and is condensed to saturated liquid at225lbf/in^2 on the outside of tubes through which cooling waterflows. In passing through the tubes, the cooling water increases intemperature by 15degree F and experiences no significant pressuredrop. The mass flow rate of cooling water is 250 lb/min. Neglectingkinetic and potential energy effects and ignoring heat transferfrom the outside of the condenser,determine the mass flow rate ofammonia.
Explanation / Answer
Solution: Balance of mass of thecondenser: M1amonia-m2amonia+m3water-m4water = o (s.s) m1=m2=mamonia m3=m4=mwater Balance ofEnergy: Q-W+mamonia(h1 - h2) + mwater(h3 - h4 ) = 0(s.s) (Q=0 and w= 0) so the energy balancebecome: mamonia(h1 - h2 ) = mwater(h4 - h3 ) mamonia =mwater ( h4- h3) / ( h1 - h2) Q-W+mamonia(h1 - h2) + mwater(h3 - h4 ) = 0(s.s) (Q=0 and w= 0) so the energy balancebecome: mamonia(h1 - h2 ) = mwater(h4 - h3 ) mamonia =mwater ( h4- h3) / ( h1 - h2)Related Questions
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