Besides the obvious spelling error (barge begins with \"b\", not\"l\"), there ar

Question

Besides the obvious spelling error (barge begins with "b", not"l"), there are gross errors in the use of the metric system in thegiven solution.
1.) the mass of the barge is 75 Mg, which is 75*103 kg(not 75 mg, which is 75*10-9kg) - this boat is real, nota bath toy!
2.) The solution uses 75mg (0.075 g), so the resulting answeris given as: T = 0.01446N (which is incorrect because of the unitmishap)
3.) This answer is then erroneously converted to 14.46 kN, which isthe correct answer but it was derived incorrectly in thissolution. 0.01446N = 14.46mN (milliNewtons), notkN(kiloNewtons). However, as stated earlier, 14.46 kN is thecorrect answer since the mass of the barge is in Mg, not mg

Explanation / Answer

The solution you are referring is incorrect. The correct solution is: For the barge: T = Mb*a a = Vb/t = (25*5/18 m/s) / 35s = 25/126m/s2 so, T = 75*103 kg * 25/126 m/s2 = 14.88*103 N = 14.88 kN For barge and tugboat together F = (Mb+Mt)*a     = (75+50)*103 kg * 25/126m/s2 = 24.80 * 103 N = 24.80 kN

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