My question is from the beginning of the book, Chapter 1, problem 1.2 How do you
ID: 1816444 • Letter: M
Question
My question is from the beginning of the book, Chapter 1, problem 1.2How do you get the dot product of a vector "r" (4.000i - 1.000j) and a unit vector "u" (0.8319i - 0.5546j)??? The solution manual shows...
[(4.000i - 1.000j)ft] *(dot product)* (0.8319i - 0.5546j) = 3.822 ft
I am having difficulty understanding the multiplication of this. When I attempted this, I multiplied 4.000i times 0.8319i, which an "i" cross an "i" is zero. So then I did 4.000i times -0.5546j. Since 'i' cross 'j' is 'k' and it is negative, I got -2.2184k. Then I did -1.000k times 0.8319i and got 0.8319k since 'j' cross 'i' is negative 'k', but the negative 'j' turns it to a positive 'k'. So from there I was left with -2.2184k + 0.8319k = -1.3865k
So what is it that I am doing wrong since I did not get the answer 3.822???
How do you get the dot product of a vector "r" (4.000i - 1.000j) and a unit vector "u" (0.8319i - 0.5546j)??? The solution manual shows...
[(4.000i - 1.000j)ft] *(dot product)* (0.8319i - 0.5546j) = 3.822 ft
I am having difficulty understanding the multiplication of this. When I attempted this, I multiplied 4.000i times 0.8319i, which an "i" cross an "i" is zero. So then I did 4.000i times -0.5546j. Since 'i' cross 'j' is 'k' and it is negative, I got -2.2184k. Then I did -1.000k times 0.8319i and got 0.8319k since 'j' cross 'i' is negative 'k', but the negative 'j' turns it to a positive 'k'. So from there I was left with -2.2184k + 0.8319k = -1.3865k
So what is it that I am doing wrong since I did not get the answer 3.822???
Explanation / Answer
In dot product i.i = j.j=1 i.j=j.i =0 so (4.000i-1.000j) .(0.8319 i-0.5546 j) = (4.000 x 0.8319) + (1.000 x 0.5546) = 3.8822 ft ANS; It is a dot product ; you did it as a cross product. i think that yourdoubt is clarified.
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