i wanted to solve the problem as following: q=(tg-ts)/(Rfin+Rgas) Rfin=just like

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i wanted to solve the problem as following:
q=(tg-ts)/(Rfin+Rgas)

Rfin=just like the solution says

Rgas(due to convection from gas to surface area of wall)=1/[(SA)(h)]

instead of going through the specifics i just want a conceptional question answered...

why do you not have to consider the resistance of the gas? I would think that the gas would have a convection resistance that would add to the resistance of fins but the solution ignores it :/
please answer if at all possible

thank you John Allen

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