P1.28 The steel pipe column shown in Figure P1.28 has an outside diameter of 8.6

Question

P1.28
The steel pipe column shown in Figure P1.28 has an outside diameter of 8.625 in. and a wall thickness of 0.25 in. The timber beam is 10.75 in. wide, and the upper plate has the same width. The load imposed on the column by the timber beam is 80 kips. Determine:

(a)
the average bearing stress at the surfaces between the pipe column and the upper and lower steel bearing plates.

(b)
the length L of the rectangular upper bearing plate if its width is 10.75 in. and the average bearing stress between the steel plate and the wood beam is not to exceed 500 psi.

(c)
the dimension a of the square lower bearing plate if the average bearing stress between the lower bearing plate and the concrete slab is not to exceed 900 psi.

Problem is from this book, please add it to the textbooks with available solutions.

Mechanics of Materials: An Integrated Learning System by Timothy A. Philpot  

Explanation / Answer

Bearing stress is just the stress at that joint, its calculated like all other stresses, Force/Area a) Between the pipe and plate, the area in question is the surface area of the pipe (outer diameter - inner diameter). 80000 lb / (pi*4.3125^2 - pi*4.3^2) = 236537 psi b) Same equation, different variables substituted in. 500 psi = 80000 lb / (10.75 * x) Solving for x we get x = 14.884 inches c) The lower bearing plate is square, because a represents both of the sides of the plate. 900 psi = 80000 lb / (a^2) a^2 = 88.888 in^2 a = 9.428 inches

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