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Water steam at 600 kPa and 200 o C enters an insulated (adiabatic) nozzle (Figur

ID: 1816960 • Letter: W

Question

Water steam at 600 kPa and 200
o
C enters an
insulated (adiabatic) nozzle (Figure 3) with a
velocity of 50 m/s. It leaves at a pressure of 150
kPa and a velocity of 600 m/s.
(a) Determine the temperature Te of the water at
the nozzle exit.
(b) Suppose the water steam undergoes an
isentropic (adiabatic and reversible) process from
the same inlet conditions and finally reaches the
same pressure (150 kPa) at the exit, determine the
quality xes at the exit.
(c) Determine the velocity Ves at the nozzle exit in
the above isentropic process.
(d) Determine the isentropic efficiency ?nozzle of the nozzle.

Explanation / Answer

He=Hi + (Vi^2)/2 - (Ve^2)/2 Xes = Si-Sfg/sf Hes=Hf + Xes * Hfg (Ves^2)/2 = Hi - Hes + (Vi^2)/2 n = ((Ve^2)/2)/(Ves^2)/2