a) the forklift and operator have combined weight of 10000 lb and a center of gr
ID: 1817164 • Letter: A
Question
a) the forklift and operator have combined weight of 10000 lb and a center of gravity at G. if the forklift is used to lift the 2000 lb concrete pipw, determine the maximum verical acceleration it can give to the pipe so that it does not tip foward on its front wheels.
b) the forklift and operator have combined weight of 10000 lb and a center of gravity at G. if the forklift its used to lift 20000lb concrete pipe determine the normal reactions on each of its four wheels if the pipe is so that it does not tip fowarf on its front wheels.
Explanation / Answer
My FBD shows...
1) a Force up at A (the support force at wheel A),
2) A force (T) I show as coming down off the fork lift, aiming down to the 2000 lb concrete block (which is the "apparent" tensile force the line will see when lifting the weight with an acceleration)
3) The combined weight of the lift and operator (10,000 lb) coming down thru the point at G
4) I choose to make the force at tire B = 0, and assume that it is JUST touching the ground.
Perform a M about point A... which will be zero if the forklift is NOT tipping...
T(5) - 10000 (4) = 0
Gives: T= 8000 lbs (wow. This will mean that we will be able to lift the concrete pretty quickly. Let's see how fast...
Do a FBD of the concrete block with UP as (+), the direction of acceleration.
The only forces acting on the block are the T force acting UP (just calculated), and the block's Weight (2000) acting down.
Perform F = ma..... Gives
8000 - 2000 = (2000/32.2) a (Solve this for acceleration, a)
I got a = 96.6 ft/s2 (pretty fast)
For Part II... Use the above process, but go backwards....
Use a = 4, and find the resulting T force...
(as a check, i got 2248.4 lbs)
Use this T force with MA = 0 to find the force at Tire B
Then use F = 0 ( 0 for the forklift since it is NOT moving up or down!)
This will give the Force at Tire A.
That's it! Let me know how it goes!
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