The energy equation under steady state operation can be expressed as: This equat

Question

The energy equation under steady state operation can be expressed as: This equation can be re-arranged as: The second equation can be used to calculate the pressure variation betweens sections (1) and (2) and evaluate the contribution to pressure variation due to clause in velocity (kinetic energy), elevation. and energy transfer such as dull work and loss Please find the pressure difference between sections (1) and (2) and the contribution of each factor for the following case described in Q5 66 in textbook A 20 kW pimp shown in Fig P5 66 is used to pump gasoline (SG=0,68) at a volume flow rate of 0.12 m2 / s. The loss between sections (1) nod (2) is equal to 0.15

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Contributions of each element can be determined by calculating the individual parts of the last equation and are:

74.3 kPa for change in velocity (KE)

-20.0 kPa for change in elevation

166.7 kPa for pump work

-23.8 kPa for shaft loss

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