I need help desperately with this problem of thermodynamics. I will rate instant

Question

I need help desperately with this problem of thermodynamics. I will rate instantly. PLEASE provide a detailed explanation of steps. THANKS!

1) Assume that the energy contained in coal is about 10,000 Btu/lbm. An electrical power plant burning coal has an output capacity of 1200 MW and the plant converts about 30% of the input energy to electricity. How many short tons of coal are required by this plant per year, assuming it operates continuously? If 10% of the coal mass remains as residual ash, how many tons will develop in the ash pile over 25 years?

Explanation / Answer

Answer with changes and explanations for your doubts 10000 Btu/lb = 23260 kJ/kg Output = 1200 MW = 1200*10^6 watt = 1200*10^6 J/sec Output in 25 years = 1200 *10^6 * 3600*24*365*25 J = 94608*10^10 kJ Efficiency =output/input = 30% = 30/100 so, input = 100/30 * output Input required = 94608*10^10 * 100/30 = 315360*10^10 kJ mass of coal required = 315360*10^10 / 23260 = 13.558*10^10 kg = 135.58*10^3 tons Ash produced = 10% of mass of coal = mass of coal * 10/100 = 13,558 tons....

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