A field compaction control test was conducted on a compacted lift. The mass of t

Question

A field compaction control test was conducted on a compacted lift. The mass of the material removed from the hole was 1814 g and the volume of the hole was found to be 944 cm3. A small sample of the soil lost 15 g in the drying test and the mass remaining after drying was 100 g. The laboratory control test results are shown in Fig. P5-5. If end-product specification requires 100% relative compaction and w (optimum - 3%) to (optimum + 1%), determine the acceptability of the field compaction and state why this is so. If it is not acceptable, what should be done to improve the compaction so that it will meet the specification?

Explanation / Answer

Mass of soil = 1814 g Volume of soil = 944 cc Small sample water content = 100 * Mass of water in soil / Mass of dry soil Water content = 15% Dry density of soil = Mass of soil/volume of soil / (1+w) = 1814/955/1.15 =1.65 Mg/m3 Relative compaction = 1.65/1.72 *100 = 95.93 % (a) water content lies between 13.5% to 17.5% so ok Relative compaction is less than 100% so the sample given is NOT acceptable (b) Increase the water content and compact the soil further

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