This problem comes from the book, Vector Mechanics for Engineers: Dynamics 10th

Question

This problem comes from the book, Vector Mechanics for Engineers: Dynamics 10th Edition.

Explanation / Answer

BY ENERGY CONSERVATION BETWEEN POINTS A AND POINT D => M*G*(H-2R) = M*V^2 /2 => V^2= 2*G(H-2*R) .........................1 NOW AT POINT D: M*V^2 /R = M*G ...........................2 FROM 1 ST AND 2ND EQUATION => H= 5*R /2 =50 FT . BY ENERGY CONSERVATION BETWEEN POINTS A AND E => M*G(H-R)= M*V^2 /2 => V^2 = 2*G(H-R) ............3 NOW AT POINT E; M*V^2 / ROH = M*G ................4 FROM 3RD AND 4TH EQUATION => H=(ROH + 2*R ) /2 = 57.5 FT THEREFORE RANGE OF H IS FROM 50 FT T0 57.5 FT

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