The two blocks shown have masses of mA = 51 kg and mB = 73 kg . The coefficient

Question

The two blocks shown have masses of mA = 51 kg and mB = 73 kg . The coefficient of kinetic friction between block A and the inclined plane is Muk = 0.13 . The angle of the inclined plane is given by theta = 40 degree. Neglect the weight of the rope and pulley. Determine the magnitudes of the normal force acting on block A, NA. Express your answers to two significant figures in Newtons. Velocity of the Blocks at a Given Position If both blocks are released from rest, determine the velocity of block B when it has moved through a distance of s = 3.25 m . Express your answer to two significant figures and include the appropriate units. Position of the Blocks at a Given Velocity If both blocks are released from rest, determine how far block A has moved up the incline when the velocity of block B is (vB)2 = 5.75 m/s . Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Part A Na = ma*g*cos(theta) = 51*9.8*cos40 = 382.9 N Part B Friction force on block A = F = u*Na = 0.13*382.9 = 49.8N Equation for mass A T - ma*g*sin40 - F = ma*a T - 371 = 51*a {eqn 1} Equation for mass B mb*g - T = mb*a 73*9.8 -T = 73*a 715.4 - T = 73*a {eqn 2} adding eqn 1 and 2 we get a = 2.78 m/sec^2 V^2 - U^2 = 2*a*s V^2 = 2*2.78*3.25 V = 4.25 m/sec Part C V^2 - U^2 = 2*a*s (5.75)^2 = 2*2.78*s s = 5.95 m

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.