the following string of ASCII characters whose bit patterns havebeen converted i
ID: 1829473 • Letter: T
Question
the following string of ASCII characters whose bit patterns havebeen converted into hexadeciminal for compactness:73 F4 E5 76 E5 4A EF 62 73. of the 8 bits in eachpair of digits, the leftmost is a parity bit, the remaining are the ASCII code,A. convert thestring to bit form and decode the ASCII code B. determine theparity used: odd or even?
i dont reallyunderstand what the question is stating in the upper portion withit being hexa decimal so i cant convert it will rate lifesaver if someone can explain how to do this compactness:73 F4 E5 76 E5 4A EF 62 73. of the 8 bits in eachpair of digits, the leftmost is a parity bit, the remaining are the ASCII code,
A. convert thestring to bit form and decode the ASCII code B. determine theparity used: odd or even?
i dont reallyunderstand what the question is stating in the upper portion withit being hexa decimal so i cant convert it will rate lifesaver if someone can explain how to do this
Explanation / Answer
73 - 0111 0011F4 - 1111 0100
E5 - 1110 0101
T6 - 0111 0110
E5 - 1110 0101
4A - 0100 1010
EF - 1110 1111
62 - 0110 0010
73 - 01110011
Ignoring each parity bit for now and looking in Table of thetext, we can decode this string to
be “stefeJocs" as shown below: 0111 0011 -s
1111 0100 -t
1110 0101 -e
0111 0110 -v
1110 0101 -e
0100 1010 -J
1110 1111 -o
0110 0010 -c
0111 0011 -s
Now looking at the parity bit, itshould be obvious that odd parity is being used.
I hope this helpsyou.................
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