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We want to store sufficient energy in a 0.01 F capacitor to supply5 horsepower (

ID: 1829606 • Letter: W

Question

We want to store sufficient energy in a 0.01 F capacitor to supply5 horsepower (hp) for 1 hour. To what voltage must the capacitor becharged? (One horsepower is equivalent to 745.7 watts.) Does thisseem to be a practical method for storing this amount of energy? Doyou think that an electric automobile design based on capacitiveenergy storage is feasible?

Explanation / Answer

(a) Energy Stored in aCapacitor        E   = (1/2) CV2                                                     where , C = capacitance , V = voltageapplied to capacitor    Energy required in above problem ,   E =745.5*(60*60) J      (Since 1 hour = 3600seconds)       Hence   V = (2E/C)                      = (2*745.5*60*60/0.01) V               => V = 23168.1 V (b)      As seen , the requiredvoltage is nearly 23000 V which is practically infeasible , eventhough such a high voltage is used for power transmission. but itssurely not a good way to store engergy. (c) Automobiles are too small to possess device that can generate23000 V dc , and hence its not feasible to design such anautomobile. I hope this helps you

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