GIVEN two resistors r1=49 and r2=100 with powerrated 1W each. 1. what is the lar

Question

GIVEN two resistors r1=49 and r2=100 with powerrated 1W each. 1. what is the largest current Is thatcan be safely passed through the series combination of those tworesistors. 2. what is the largest voltage Vs that can beapplied to the series combination of those two resistors. 3. what is the largest voltage Vp that can besafely applied to the parallel combination of these twocircuits? 4.if the resistor r1 alone dissipates 0.8J energy in 2seconds, what is the voltage V1? GIVEN two resistors r1=49 and r2=100 with powerrated 1W each. 1. what is the largest current Is thatcan be safely passed through the series combination of those tworesistors. 2. what is the largest voltage Vs that can beapplied to the series combination of those two resistors. 3. what is the largest voltage Vp that can besafely applied to the parallel combination of these twocircuits? 4.if the resistor r1 alone dissipates 0.8J energy in 2seconds, what is the voltage V1?

Explanation / Answer

we know Power(W)= Voltage(V) x Current(I)                =V x I                = (I x R) x I                = I2R Maximum allowable current through r1 is .1428A and r2 is.1A The largest current that can pass safely through r1-r2 is the.1A, since excess of .1A will damage r2. So the maximum voltage that u can apply is (R1 + R2)x.1=14.9˜15v maximum voltage that can be given across r1 is I x R=.1428 x49=7v maximum voltage that can be given across r2 is I x R=.1 x100=10v So the maximum voltage that u can apply when r1 r2 are inparallel is 7v, becoz excess of 7v will damager1 Resistor r1 dessipates .8J in 2 seconds power = .4W Current=(W/R)=(.4 /49 ) = .09A Voltage (V1) = V x I = 4.4V

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