Given that A = a + jb and B = c + jd, where a = 10; b=-2; c = 6; and d = -8. Not

Question

Given that A = a + jb and B = c + jd, where a = 10; b=-2; c = 6; and d = -8. Note that all phase angles should beexpressed as values between -180 degrees and +180 degrees( or -piradius and +pi radius). 1. Find the real part of A and B. 2. Find the imaginary part of A and B. 3. Find the magnitude of A. 4. Find the phase angle of A.     ______________degrees 5. Find the magnitude of B. 6. Find the phase angle of B.    ______________radians. 7. Find the magnitude of the quotient A/B. 8. Find the phase of the quotient A/B.     _____________degrees Given that A = a + jb and B = c + jd, where a = 10; b=-2; c = 6; and d = -8. Note that all phase angles should beexpressed as values between -180 degrees and +180 degrees( or -piradius and +pi radius). 1. Find the real part of A and B. 2. Find the imaginary part of A and B. 3. Find the magnitude of A. 4. Find the phase angle of A.     ______________degrees 5. Find the magnitude of B. 6. Find the phase angle of B.    ______________radians. 7. Find the magnitude of the quotient A/B. 8. Find the phase of the quotient A/B.     _____________degrees

Explanation / Answer

A=10+[-2]j B=6+[-8]j 1)The real part of A is a=10 The real part of B is c=6 2)The imaginary part of A is b=-2 The imaginary part of B is d=-8 3)Magnitude ofA=|[a2+b2]|=104 5)the imaginary part of B=|(c2+d2)|=10 4)the phase angle of A =tan-1b/a =tan-1-2/10=168.7 degrees 6)the phase angle of B=tan-1d/c=tan-1-8/6=.927 radians 7)A/B=10-2j/6-8j=(10-2j)(6+8j)/(6-8j)(6+8j)=[60-12j+80j-16j2]/36+64    [j2=-1]                              = 76+68j/100=76/100 +j68/100 8)phase of A/B = tan-168/76 =41.8 degrees

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