f = x1x2’x3’ + x1x2x4 +x1x2’x3x4’ = x1x2’x3’(x4’ + x4) + x1x2x4 +x1x2’x3x4’ = x1
ID: 1831140 • Letter: F
Question
f = x1x2’x3’ + x1x2x4 +x1x2’x3x4’ = x1x2’x3’(x4’ + x4) + x1x2x4 +x1x2’x3x4’ = x1x2’x3’x4’ + x1x2’x3’x4 +x1x2x4 + x1x2’x3x4’ = x1x2’x3’ + x1x2’(x3’ + x3)x4 +x1x2x4 = x1x2’x3’ + x1x2’x4’ + x1x2x4this is the answer, but I don't understand what theorem isused from line 3 to 4, how does the last term set in line 3 changefrom x1x2’x3x4' to x1x2x4. Where does the x3go and how does x4 become primed? Then from line 4 to line 5,how does the middle term's 4x become primed? f = x1x2’x3’ + x1x2x4 +x1x2’x3x4’ = x1x2’x3’(x4’ + x4) + x1x2x4 +x1x2’x3x4’ = x1x2’x3’x4’ + x1x2’x3’x4 +x1x2x4 + x1x2’x3x4’ = x1x2’x3’ + x1x2’(x3’ + x3)x4 +x1x2x4 = x1x2’x3’ + x1x2’x4’ + x1x2x4
this is the answer, but I don't understand what theorem isused from line 3 to 4, how does the last term set in line 3 changefrom x1x2’x3x4' to x1x2x4. Where does the x3go and how does x4 become primed? Then from line 4 to line 5,how does the middle term's 4x become primed?
Explanation / Answer
there has been typograhical error while doing step 4 from3..also the method is not correct...it should be done in followingway
f = x1x2’x3’ + x1x2x4 + x1x2’x3x4’ = x1x2’x3’(x4’ + x4) + x1x2(x3+x3')x4 +x1x2’x3x4’ as x4+x4'=1
= x1x2’x3’x4’ + x1x2’x3’x4 +x1x2x3x4+x1x2x3'x4 + x1x2’x3x4’
=[x1x2'x3'x4'+x1x2'x3x4']+[x1x2'x3'x4+x1x2x3'x4]+x1x2x3x4
=x1x2'x4'(x3+x3')+x1x2'x3'(x4+x4')+x1x2x3x4
=x1x2'x4'+x1x2'x3'+x1x2x3x4
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