f ? G ?=? R T ln K Under conditions other than standard state, the following equ
ID: 852624 • Letter: F
Question
f
?G?=?RTlnK
Under conditions other than standard state, the following equation applies:
?G=?G?+RTlnQ
Part A
C2H2(g)+2H2(g)?C2H6(g)
The equilibrium constant of a system, K, can be related to the standard free energy change, ?G, using the following equation:?G?=?RTlnK
where T is a specified temperature in kelvins (usually 298 K) and R is equal to 8.314 J/(K?mol).Under conditions other than standard state, the following equation applies:
?G=?G?+RTlnQ
In this equation, Q is the reaction quotient and is defined the same manner as K except that the concentrations or pressures used are not necessarily the equilibrium values.Part A
Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. The reaction isC2H2(g)+2H2(g)?C2H6(g)
Given the following data at standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K), what is the value of Kp for this reaction? Substance ?G?f(kJ/mol) C2H2(g) 209.2 H2(g) 0 C2H6(g) ?32.89
Explanation / Answer
Assuming a temperature of 298 K,
K = e^(242,090 J*(1/298K)*(1/8.314))
K = 2.7 X10^42
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