Prior to t=0, v1=100V and v2=0. D) Find an expression for the current as a funct

Question

Prior to t=0, v1=100V and v2=0.

D) Find an expression for the current as a function of time.

Prior to t=0, v1=100V and v2=0. next stepE) Find the value that v2 approaches as t becomes very large. next step D) Find an expression for the current as a function of time. next stepC) What is the value of the time constant in this circuit?next stepB) Write the KVL equation for the circuit in terms of the current and initial voltages. Take the derivative to obtain a differential equation. next stepA) Immediately after the switch is closed, what is the vale of the current [i.e. what is the value of i(0+)]

Explanation / Answer

Just to start you off.... We can assume the initial voltage is (V1), at V1(0-) = V1(0+); because the voltage of a capacitor cannot change instantaneously... Therefore, V2(0), when the switch is closed is zero (0). Now. using KVL. we can solve for I(t) when t=0+. -V1(0) + I(0)*R + V2(0) = 0. Therefore, I(0) = (100 V) / (200kOhms)

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