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Equations 3 and 4 provide the expressions for transfer function of simplest low-

ID: 1832353 • Letter: E

Question

Equations 3 and 4 provide the expressions for transfer function of simplest low-pass and high-pass filters respectively. a represents the cutoff frequency. These filters can be implemented using an RC circuit. HL(f) = a/a + j2pif HH(f) = 1 - a/a + j2pif HL(f) of a real low-pass filter typically has low, but non-zero, values at high frequencies, and a gradual drop in magnitude as the frequency increases. HH(f) of a real high-pass filter typically has low, but non-zero, values at low frequencies, and a gradual rise in magnitude as the frequency increases. Given sampling frequency of f8 =8000 Hz and frequency resolution of 10 Hz, plot the magnitude of HL(f) and HH(f) for for your desired cutoff frequency

Explanation / Answer

yes