Below is a picture of a light emitting diode (LED) circuit, like the one built i

Question

Below is a picture of a light emitting diode (LED) circuit, like the one built in class, and a corresponding circuit schematic. A volt meter was used to measure the voltage across each circuit element and the results are recorded in the table below. Draw the circuit on your solution and provide answers to the questions. Use Ohm's law to determine the current and then use KCL to determine the value of the other currents. Enter these values in a corresponding table in your solutions. Since for each circuit element, the voltage reference signs and the current reference arrow are chosen according to "passive sign notation'', the product of i and v is the power absorbed by that element. Fill in the rest of the table and show that energy balance results. Determine the value of the variable resistor in ohms.

Explanation / Answer

all currents will be same because of series circuit using ic = Vc / Rc = 1.15/100 = .0115A now in series circuit iA = iB = iC = iD = .0115A power = vi pA = .10825W pB = .071185W pC = .013325 pD = .023805W rB = vB/iB = 538.26 ohm

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